Question 12

Jambmaths question: 

Given that θ is an acute and $\tan =\tfrac{12}{5}$ find sin θ

Option A: 

$\tfrac{12}{13}$

Option B: 

$\tfrac{5}{12}$

Option C: 

$\tfrac{13}{5}$

Option D: 

$\tfrac{5}{13}$

Jamb Maths Solution: 

Using Pythagoras theorem

$AC=\sqrt{{{12}^{2}}+{{5}^{2}}}=13$

$\sin \theta =\frac{opp}{hyp}=\frac{AB}{AC}=\frac{12}{13}$

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