Question 24

Jambmaths question: 

Find the mean of the distribution

X

21

22

23

24

25

26

36

F

3

4

2

6

1

1

3

 

Option A: 

20

Option B: 

23

Option C: 

25

Option D: 

21

Jamb Maths Solution: 

$\begin{align}  & \bar{x}=\frac{\left[ (21\times 3)+(22\times 4)+(23\times 2)+(24\times 6)+(25\times 1)+(26\times 1)+(36\times 3) \right]}{3+4+2+6+1+1+3} \\ & \bar{x}=\frac{63+88+46+144+25+26+108}{20}=\frac{500}{20} \\ & \bar{x}=25 \\\end{align}$

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