Question 30

Jambmaths question: 

If p varies inversely as the square of q and p = 4, find p when q = 2

Option A: 

32

Option B: 

12

Option C: 

16

Option D: 

25

Jamb Maths Solution: 

$\begin{align}  & p\propto \frac{1}{{{q}^{2}}} \\ & p=\frac{k}{{{q}^{2}}}\text{  (}k=\text{constant of variation)} \\ & k=p{{q}^{2}}=4\times {{5}^{2}}=100 \\ & p=\frac{100}{{{2}^{2}}}=25 \\\end{align}$

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